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OpenStudy (anonymous):
what is the area of a right triangle whose height is x and hypotenuse is y?
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OpenStudy (anonymous):
0.5(\[\sqrt{y ^{2}-x ^{2}}\]*(x)
OpenStudy (anonymous):
A = 1/2(base)(height) the height is given which is your x. so, you have to find the base. in order to find the base, use the pythagorean theorem c^2 = a^2 + b^2 so, y^2 = x^2 + b^2 then, b = \[\sqrt{y ^{2}-x ^{2}}\] Area = \[(x/2)(\sqrt{y ^{2}-x ^{2}})\]
OpenStudy (anonymous):
same stuff
OpenStudy (anonymous):
Thank you so much! This will really help in helping me study!
OpenStudy (anonymous):
no problem
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OpenStudy (anonymous):
your welcome.
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