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OpenStudy (anonymous):

what is the area of a right triangle whose height is x and hypotenuse is y?

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OpenStudy (anonymous):

0.5(\[\sqrt{y ^{2}-x ^{2}}\]*(x)

OpenStudy (anonymous):

A = 1/2(base)(height) the height is given which is your x. so, you have to find the base. in order to find the base, use the pythagorean theorem c^2 = a^2 + b^2 so, y^2 = x^2 + b^2 then, b = \[\sqrt{y ^{2}-x ^{2}}\] Area = \[(x/2)(\sqrt{y ^{2}-x ^{2}})\]

OpenStudy (anonymous):

same stuff

OpenStudy (anonymous):

Thank you so much! This will really help in helping me study!

OpenStudy (anonymous):

no problem

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OpenStudy (anonymous):

your welcome.

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