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Mathematics
OpenStudy (anonymous):

My problem is attached, Thanks!

OpenStudy (anonymous):

Here,

OpenStudy (anonymous):

two triangles ABC and abc I think Aa and Bb and Cc lines converge in center of dilation

OpenStudy (anonymous):

ratio is ab/AB =ac/AC =bc/BC

OpenStudy (anonymous):

Thanks, what does it mean by scale the factor of the dilation?

OpenStudy (anonymous):

A scale factor is a number which scales, or multiplies, some quantity. In the equation y=Cx, C is the scale factor for x. C is also the coefficient of x, and may be called the constant of proportionality of y to x. For example, doubling distances corresponds to a scale factor of 2 for distance, while cutting a cake in half results in pieces with a scale factor of ½.

OpenStudy (anonymous):

okay, and did you find the center?

OpenStudy (anonymous):

let me see again the diagram plz

OpenStudy (anonymous):

Its at the top.

OpenStudy (anonymous):

please chek my nums: A(-6,0) ,a(-2,0) B(6,-6) , b(2,-2) Aa: y=0

OpenStudy (anonymous):

Bb: m=-1 y+2=-1(x-2) y=-x-4

OpenStudy (anonymous):

they are correct

OpenStudy (anonymous):

-x-4=0: x=-4 (-4,0) it,s not true!

OpenStudy (anonymous):

is it?

OpenStudy (anonymous):

hhmm... not too sure either

OpenStudy (anonymous):

my x component is wrong. why?

OpenStudy (anonymous):

I don't know what to tell ya. You were on a roll!

OpenStudy (anonymous):

y=-x-4 is false! y=-x. do you agree?

OpenStudy (anonymous):

so -x=0 x=0 (0,0)

OpenStudy (anonymous):

I can't tell you I agree. This is a problem from way back, and I've forgotten all of the mechanics. I think your on to something though. Or at least I hope... lol

OpenStudy (anonymous):

I hve forgotten too :)

OpenStudy (anonymous):

haha! Thanks for trying though!

OpenStudy (anonymous):

sorry if i could not help u:)

OpenStudy (anonymous):

No problem, I'll try re-posting later!

OpenStudy (radar):

The problem i have is with the drawing. You have to guess the locations as the points are not expressed like (x,y)

OpenStudy (anonymous):

ya that sucks

OpenStudy (radar):

like the two lines that converge on the negative x axis a guess would be -6 but that would be just a guess.

OpenStudy (radar):

The vertical line that is the base of the large triangle looks to have a segment of the line x=6, but I am not sure.

OpenStudy (anonymous):

I think 6 is the point for both of those.

OpenStudy (radar):

You would think they would of stated it so, rather than leave a student guessing. The diagram appears to me that the triangles are skewed a little bit so that the x axis does not go through the midpoint of the larger triangles base.

OpenStudy (anonymous):

Tell me about it! Thanks for your sympathy.

OpenStudy (radar):

Sorry but that is all I can offer! Like you say maybe a reposting and someone like satellite, amister or polpak will see it.

OpenStudy (anonymous):

Thanks! I will try that.

OpenStudy (amistre64):

this one eh?

OpenStudy (anonymous):

yes!!!

OpenStudy (amistre64):

do we have any option to choose from? as in multiple choices?

OpenStudy (anonymous):

Sadly no, I have show my work.

OpenStudy (amistre64):

this is what I assume the points to be

OpenStudy (anonymous):

looks good

OpenStudy (amistre64):

id have to look up what 'scale dilution' means, but I think its just the scaled factor; find the distances of each line segment

OpenStudy (amistre64):

12 4 --- as --- ; is a scale of 1:3 if i see it right 3 1

OpenStudy (amistre64):

but the dilution is not centered to the bigger tri, so let me look into that

OpenStudy (amistre64):

scale is either 1:3 or 3:1 that i see, does that make sense? the center of the dilution is the points where the lines cross from angle to midsection ..

OpenStudy (anonymous):

Do you think I would need to park the spot like with the paint tool?

OpenStudy (amistre64):

OpenStudy (amistre64):

determine the equations of 2 of those lines; and see where they match up

OpenStudy (amistre64):

(-2,0) (2, -1/2) is one line (2,1) (0,1) appears to be the other

OpenStudy (amistre64):

slope = -1/8 y-0 = -1/8(x-(-2)) y = (-1/8)x - (1/4)

OpenStudy (amistre64):

(2,1) -(0,-1) ------ 2,2 ; slope = y/x = 1 y-1 = x -2 y = x-1 is the other equation

OpenStudy (amistre64):

when: x-1 = (-1/8)x - (1/4) we have the center of the diulted triangle right?

OpenStudy (amistre64):

x + (1/8)x = (-1/4) +1 9/8 x = 3/4 x = 8(3)/9(4) = 2(1)/3(1) = 3/2 y = (2/3) -1 = 2/3 - 3/3 = -1/3 the center appears to be at: \[(\frac{3}{2},-\frac{1}{3})\]

OpenStudy (anonymous):

Wow. First off my apologies, secondly a huge round of plausible! Thank you so much, I had no idea. One little question before you go: How do you find the area of a circle in pi when your given the entire diameter?

OpenStudy (amistre64):

Area and Circumference have a radius in common; and Radius = half the diameter

OpenStudy (anonymous):

applause*

OpenStudy (amistre64):

Area = pi r^2

OpenStudy (amistre64):

was my diluted tri correct? :)

OpenStudy (anonymous):

I'm not really sure! But again, so i divide the diameter in half, and then what?

OpenStudy (amistre64):

(d/2)^2 * pi

OpenStudy (amistre64):

if diam = 10; then Area = (10/2)^2 pi = 25 pi

OpenStudy (anonymous):

Got it! thank you so, so, so much!

OpenStudy (radar):

Thanks amistre64, I was lost without the points be given.

OpenStudy (amistre64):

:) i had to assume points as well

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