Question

this my my simple question :
lim x-0 (√x+2-√2/x)
help any ideas

Answer 1

is x under whole thing or just under sqrt[2]

Answer 2

yes is under whole

Answer 3

Multiply top and bottom by
Sqrt[x+2]+Sqr[2]

Answer 4

Then you would be able to cancel x

Answer 5

1/sqrt[x+2]+Sqrt[2]
1/sqrt[2]+sqrt[2]
1/2(sqrt[2])

Answer 6

infinite
cayse lim=f(0) so u'll have sqr(0+2)-sqr(2/0)
limsqr2=sqr2 and limsqr2/0=infinite
sqr2-infinte=-infinite

Answer 7

\[\lim_{x \rightarrow 0} (\sqrt{x+2}-\sqrt{2}) / x = \lim (x+2-2)/ x(\sqrt{x+2} +\sqrt{2})= \lim 1/\sqrt{x+2} +\sqrt{2}=1/(2\sqrt{2})\]

Answer 8

thanks very much