Mathematics OpenStudy (anonymous):

How do you solve a 4x4 Matrix? OpenStudy (anonymous):

You can in many ways OpenStudy (anonymous):

what is one way? OpenStudy (anonymous):

Inverse solving OpenStudy (anonymous):

could you explain? OpenStudy (anonymous):

Gaussian Elimination OpenStudy (anonymous):

4 x 4 ? a b c d e f g h i j k l m n o p it it (afkp) + (bglm) + (chin) + (ejod) - (dgjm) - (hkna) - (cfip) - (belo) ???? I hope I made the question clear enough to not take up too much of your time. http://www.math.ubc.ca/~israel/applet/mcalc/matcalc.html (matrices calculator.) OpenStudy (anonymous):

thanx beehive OpenStudy (anonymous):

imranmeah91 could you explain the Gaussian Elimination OpenStudy (anonymous):

Hold on OpenStudy (anonymous):

k thanx OpenStudy (amistre64):

$\begin{array}c a&b&c&d\\ e&f&g&h\\ i&j&k&l\\ m&n&o&p\\ \end{array}$ $\begin{array}c a&b&c&d\\ e&f&g&h\\ i&j&k&l\\ m&n&o&p\\ \end{array}\*] <- remove the * to format OpenStudy (anonymous): amistre64: i didnt understand that OpenStudy (anonymous): Hold on, I am trying to format OpenStudy (amistre64): that is the code you type in to format a matrix so its readable OpenStudy (anonymous): copy it into where? OpenStudy (anonymous): we will just try to solve 2 by 2 matrix 2x+3y=2 -2x+x=6 OpenStudy (anonymous): but i want to know how to solve it by hand OpenStudy (anonymous): i understand a 2x2 matrix imranmeah91 but i need a 4x4 OpenStudy (anonymous): \[\left( \begin{array}{cc} 2 & 3 \\ -2 & 1 \end{array} \right)|\left( \begin{array}{c} 2 \\ 6 \end{array} \right)$ OpenStudy (anonymous):

wait...not a system of equations by matrices... just a 4x4 OpenStudy (anonymous):

Just 4 x 4 ? then what would you be finding? OpenStudy (anonymous):

the determinant OpenStudy (anonymous):

sry i should have said that earlier OpenStudy (anonymous):

no problem OpenStudy (amistre64):

got any input values in specific? OpenStudy (anonymous):

amistre64: not rele OpenStudy (anonymous):

$\left( \begin{array}{cccc} 1 & 2 & 3 & 4 \\ 5 & 6 & 7 & 8 \\ 12 & 11 & 10 & 9 \\ 1 & 3 & 2 & 7 \end{array} \right)$ OpenStudy (amistre64):

that det() = 0 on my ti83 OpenStudy (anonymous):

so how do you solve it? OpenStudy (anonymous):

Use coefficient rule $\left( \begin{array}{ccc} 6 & 7 & 8 \\ 11 & 10 & 9 \\ 3 & 2 & 7 \end{array} \right)-2\left( \begin{array}{ccc} 5 & 7 & 8 \\ 12 & 10 & 9 \\ 1 & 2 & 7 \end{array} \right)+3\left( \begin{array}{ccc} 5 & 6 & 8 \\ 12 & 11 & 9 \\ 1 & 3 & 7 \end{array} \right)-4\left( \begin{array}{ccc} 5 & 6 & 7 \\ 12 & 11 & 10 \\ 1 & 3 & 2 \end{array} \right)$ OpenStudy (anonymous):

Now break it apart once more OpenStudy (anonymous):

? OpenStudy (anonymous):

$1\left(6\left( \begin{array}{cc} 10 & 9 \\ 2 & 7 \end{array} \right)-7\left( \begin{array}{cc} 11 & 9 \\ 3 & 7 \end{array} \right)+8\left( \begin{array}{cc} 11 & 10 \\ 3 & 2 \end{array} \right)\right)-2\left(5\left( \begin{array}{cc} 10 & 9 \\ 2 & 7 \end{array} \right)-7\left( \begin{array}{cc} 12 & 9 \\ 1 & 7 \end{array} \right)+8\left( \begin{array}{cc} 12 & 10 \\ 1 & 2 \end{array} \right)\right)+3\left(5\left( \begin{array}{cc} 11 & 9 \\ 3 & 7 \end{array} \right)-6\left( \begin{array}{cc} 12 & 9 \\ 1 & 7 \end{array} \right)+8\left( \begin{array}{cc} 12 & 11 \\ 1 & 3 \end{array} \right)\right)-4\left(5\left( \begin{array}{cc} 11 & 10 \\ 3 & 2 \end{array} \right)-6\left( \begin{array}{cc} 12 & 10 \\ 1 & 2 \end{array} \right)+7\left( \begin{array}{cc} 12 & 11 \\ 1 & 3 \end{array} \right)\right)$ OpenStudy (anonymous):

kk i get it thanx a lot imranmeah91 OpenStudy (anonymous):

hey btw how do i give a medal? OpenStudy (anonymous):

click the good answer next to my name

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