Question

Simplify secx times cosx div1+sinx

Answer 1

can anyone please help to solve this

Answer 2

\[secx*\frac{cosx}{1+sinx}=\frac{1}{cosx}*\frac{cosx}{1+sinx}=\frac{1}{1+sinx}*\frac{1-sinx}{1-sinx}=\frac{1-sinx}{1-\sin^2x}\]
=\[\frac{1-sinx}{\cos^2x}=\frac{1}{\cos^2x}-\frac{sinx}{\cos^2x}=\sec^2x-tanxsecx=secx(1-tanx)\]

Answer 3

r we suppose to show it equals something?

Answer 4

no we r suppose to show its simple form and the answer might be tanx

Answer 5

hmmm i got secx(1-tanx) not tanx

Answer 6

who said it might be tanx?
that is wrong
my simplification above looks flawless

Answer 7

yeah your answer is flawless it is possible that the question is wrong

Answer 8

did i write the question down correctly?

Answer 9

\[\sec x \times (\cos x/1+\sin x)\]

Answer 10

1+sinx is in the denominator not just 1 right?

Answer 11

right