Simplify secx times cosx div1+sinx

Question

anonymous · Answer

can anyone please help to solve this

myininaya · Answer

$$secx*\frac{cosx}{1+sinx}=\frac{1}{cosx}*\frac{cosx}{1+sinx}=\frac{1}{1+sinx}*\frac{1-sinx}{1-sinx}=\frac{1-sinx}{1-\sin^2x}$$
=$$\frac{1-sinx}{\cos^2x}=\frac{1}{\cos^2x}-\frac{sinx}{\cos^2x}=\sec^2x-tanxsecx=secx(1-tanx)$$

myininaya · Answer

r we suppose to show it equals something?

anonymous · Answer

no we r suppose to show its simple form and the answer might be tanx

myininaya · Answer

hmmm i got secx(1-tanx) not tanx

myininaya · Answer

who said it might be tanx?
that is wrong
my simplification above looks flawless

anonymous · Answer

yeah your answer is flawless it is possible that the question is wrong

myininaya · Answer

did i write the question down correctly?

anonymous · Answer

$$\sec x \times (\cos x/1+\sin x)$$

myininaya · Answer

1+sinx is in the denominator not just 1 right?

anonymous · Answer

right