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OpenStudy (anonymous):
Simplify secx times cosx div1+sinx
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OpenStudy (anonymous):
can anyone please help to solve this
myininaya (myininaya):
\[secx*\frac{cosx}{1+sinx}=\frac{1}{cosx}*\frac{cosx}{1+sinx}=\frac{1}{1+sinx}*\frac{1-sinx}{1-sinx}=\frac{1-sinx}{1-\sin^2x}\] =\[\frac{1-sinx}{\cos^2x}=\frac{1}{\cos^2x}-\frac{sinx}{\cos^2x}=\sec^2x-tanxsecx=secx(1-tanx)\]
myininaya (myininaya):
r we suppose to show it equals something?
OpenStudy (anonymous):
no we r suppose to show its simple form and the answer might be tanx
myininaya (myininaya):
hmmm i got secx(1-tanx) not tanx
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myininaya (myininaya):
who said it might be tanx? that is wrong my simplification above looks flawless
OpenStudy (anonymous):
yeah your answer is flawless it is possible that the question is wrong
myininaya (myininaya):
did i write the question down correctly?
OpenStudy (anonymous):
\[\sec x \times (\cos x/1+\sin x)\]
myininaya (myininaya):
1+sinx is in the denominator not just 1 right?
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OpenStudy (anonymous):
right
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