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OpenStudy (anonymous):
can you combine the radical 3√6-2√2
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OpenStudy (anonymous):
I don't think so
OpenStudy (anonymous):
not like terms right?
OpenStudy (anonymous):
\[=\sqrt{2}(3\sqrt{3}-2)\]
OpenStudy (anonymous):
You can`t because its not the same number under the radical
OpenStudy (anonymous):
\[\sqrt{6}=\sqrt{3}*\sqrt{2}\]
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OpenStudy (anonymous):
are we good?
OpenStudy (anonymous):
how is it that?
OpenStudy (anonymous):
\[you have \sqrt{6}=\sqrt{3*2}=\sqrt{3}*\sqrt{2}\] see it?
OpenStudy (anonymous):
How do you combine \[\sqrt{3}\] and \[\sqrt{2}\]?
OpenStudy (anonymous):
\[3\sqrt{6}-2\sqrt{2}=3\sqrt{3*2}-2\sqrt{2}=3\sqrt{3}\sqrt{2}-2\sqrt{2}=\sqrt{2}*(3\sqrt{3}-2)\]
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OpenStudy (anonymous):
\[\sqrt{2}\] is common multiplier
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