Question

can you combine the radical 3√6-2√2

Answer 1

I don't think so

Answer 2

not like terms right?

Answer 3

\[=\sqrt{2}(3\sqrt{3}-2)\]

Answer 4

You can`t because its not the same number under the radical

Answer 5

\[\sqrt{6}=\sqrt{3}*\sqrt{2}\]

Answer 6

are we good?

Answer 7

how is it that?

Answer 8

\[you have \sqrt{6}=\sqrt{3*2}=\sqrt{3}*\sqrt{2}\]
see it?

Answer 9

How do you combine \[\sqrt{3}\] and \[\sqrt{2}\]?

Answer 10

\[3\sqrt{6}-2\sqrt{2}=3\sqrt{3*2}-2\sqrt{2}=3\sqrt{3}\sqrt{2}-2\sqrt{2}=\sqrt{2}*(3\sqrt{3}-2)\]

Answer 11

\[\sqrt{2}\] is common multiplier