Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
let's call x= hours second cyclist biking to the meeting point. then he'll travel: 10x miles right?
1st one will travel 3 hours more, so (x+3)*6 = distance to the meeting point
now, because they met: 10x=6(x+3) solve it for x
did you get your answer?
4.5 hours :) got to go...
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