why doesnt x^3-8=(x-2)^3??? please reply!

Question

amistre64 · Answer

becasue they are 2 different operations

amistre64 · Answer

exponents are(nt) distributive across addition

anonymous · Answer

In one you are cubing the x and subtracting the 8. In the other you are subtracting the 2 then cubing it.
On a side not: I WANNA BE A MOD AMISTRE!!!

anonymous · Answer

because (x-2)^3 is like (x-2)(x-2)(x-2)

anonymous · Answer

so, it doesn't equal the same as x^3-8

anonymous · Answer

AMISTRE!!! D: My lip is poking out :(

anonymous · Answer

Multiply out $$(x-2)^3$$ and you will see that the answer is not $$x^3-8$$

anonymous · Answer

In general:
$$(a+b)^n \neq a^n+b^n$$

anonymous · Answer

but how would u know it is (x-2)(x^2+2x+4)

anonymous · Answer

We agree that 2^3=2*2*2?
So:
(x-2)^3=(x-2)(x-2)(x-2)
So you can get:
(x-2)(x^2+2x+4)

anonymous · Answer

ohhh i understand thanks so muh guys!