Question

why doesnt x^3-8=(x-2)^3??? please reply!

Answer 1

becasue they are 2 different operations

Answer 2

exponents are(nt) distributive across addition

Answer 3

In one you are cubing the x and subtracting the 8. In the other you are subtracting the 2 then cubing it.
On a side not: I WANNA BE A MOD AMISTRE!!!

Answer 4

because (x-2)^3 is like (x-2)(x-2)(x-2)

Answer 5

so, it doesn't equal the same as x^3-8

Answer 6

AMISTRE!!! D: My lip is poking out :(

Answer 7

Multiply out \[(x-2)^3\] and you will see that the answer is not \[x^3-8\]

Answer 8

In general:
\[(a+b)^n \neq a^n+b^n\]

Answer 9

but how would u know it is (x-2)(x^2+2x+4)

Answer 10

We agree that 2^3=2*2*2?
So:
(x-2)^3=(x-2)(x-2)(x-2)
So you can get:
(x-2)(x^2+2x+4)

Answer 11

ohhh i understand thanks so muh guys!