if you get 0 when you set y to 0 does that indicate a turning point, or just not a max/min point
?
this is 'setting y'=0' i mean i have a function, and am meant to find the max or min
so i get the derivative of that right? to find slope... and so i set say y'=3x+4 to 0

so 0=3x+4 IF that comes out as zero = zero (i know this one wont) does that mean i have a turning point or just that i've done the quesiton wrong or something else?

Question

if you get 0 when you set y to 0 does that indicate a turning point, or just not a max/min point
?
this is 'setting y'=0' i mean i have a function, and am meant to find the max or min
so i get the derivative of that right? to find slope... and so i set say y'=3x+4 to 0

so 0=3x+4    IF that comes out as zero = zero (i know this one wont) does that mean i have a turning point or just that i've done the quesiton wrong or something else?

anonymous · Answer

That just means your potential max/min is at zero. You won't get a 0=0 You'll get x=0 or something similar unless its like y'=3. That is never zero.

amistre64 · Answer

extrema HAVE zero values for slope; but there are instances where an inflection can also have 0 zlope

anonymous · Answer

Exactly. In general. y'=0 does NOT imply that y''=0.

amistre64 · Answer

but if your derivative is a linear; that means it came from a quadratic; and they have no inflections

amistre64 · Answer

0=3x+4 when x = -4/3

<.........(-4/3)...........>
      -                +

this goes from - to + slopes which means you have a minimum

anonymous · Answer

ok

anonymous · Answer

yay i can reply