Question

x^2+y^2+4y=0 graph find the center and radius

Answer 1

x^2 + (y+2)^2 -4=0
x^2 + (y+2)^2=2^2

Answer 2

so, the radios r=2
and the center: (0,-2)

Answer 3

this one is tricky. the general formula for a circle is

\[(x - h)^{2} + (y - k)^{2} = r ^{2}\]

so, you have to make the equation like this one.

(x - 0)^2 + (Y^2 + 4y) = 0

the problem is in Y. so you have to complete the square.

(x-0)^2 + (y +2)^2 = 4

the center is (0,-2)

and the radius is 2.