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Mathematics
OpenStudy (anonymous):

whats the limits as x approaches 0 fro the negative side of the function x-2 |x|over |x|?

OpenStudy (anonymous):

\[\lim_{x\rightarrow ^-0}{|x|(x-2)\over |x|}\] This?

OpenStudy (anonymous):

yeah sleek-feathered one that

OpenStudy (anonymous):

i dont knwo how to work the equation tab good

OpenStudy (anonymous):

Well, if x is something very close to 0 (but negative) what will happen with that expression?

OpenStudy (anonymous):

its comming from the negative side

OpenStudy (anonymous):

Right. That means that it is very very small (close to 0) and it is also negative.

OpenStudy (anonymous):

i could take the negative sign on the absolute value

OpenStudy (anonymous):

is this problem written correctly? if so, the abs values can cancel

OpenStudy (anonymous):

so the answer is -2

OpenStudy (anonymous):

they cancel out , r us sure

OpenStudy (anonymous):

That's correct. The absolute values will cancel for any value of x that is not 0

OpenStudy (anonymous):

(Which includes values of x that are close to 0)

OpenStudy (anonymous):

So the answer is -2

OpenStudy (anonymous):

remember, anything over itself just equals 1

OpenStudy (anonymous):

except 0.

OpenStudy (anonymous):

no need to even evaluate the limit inside the abs value

OpenStudy (anonymous):

x/x = 1 though

OpenStudy (anonymous):

as long as x is not 0 ;p

OpenStudy (anonymous):

|x|/|x| =1

OpenStudy (anonymous):

that was a stupid trick question cooked up in a calc textbook

OpenStudy (anonymous):

your taking the liimit from positve zero though mathgirl...

OpenStudy (anonymous):

That doesn't matter because it's the limit as it approaches 0, not the value at 0

OpenStudy (anonymous):

you're taking the limit of a function, and the function can be simplified first, can it not?

OpenStudy (anonymous):

\[{x \over x} = 1, \forall x \ne 0\]

OpenStudy (anonymous):

depends what rule is needed

OpenStudy (anonymous):

i guess, yes, your right

OpenStudy (anonymous):

its a big z on the graphing calculator.lol

OpenStudy (anonymous):

it approches -1 from the right and -3 from the left.

OpenStudy (anonymous):

That's not right unless we have the expression wrong above. It would have the same limit from either side (-2).

OpenStudy (anonymous):

Yeah, it does have the same limit both ways, but Calc textbooks are goofy like that so who knows.

myininaya (myininaya):

is it what polpak had or is it \[\frac{x-2|x|}{|x|}\]

OpenStudy (anonymous):

Ah.. yeah that would be different.

OpenStudy (anonymous):

totally

myininaya (myininaya):

hey polpak you are green!

OpenStudy (anonymous):

I know!

myininaya (myininaya):

lol can i be pink?

myininaya (myininaya):

hey mitlearner so the expression polpak wrote is exactly what you see in the text right?>

OpenStudy (anonymous):

I guess we'll never know ;p

OpenStudy (anonymous):

Are you deleting your posts?

OpenStudy (anonymous):

hey polpak, how come you are green?

myininaya (myininaya):

hes a moderator

OpenStudy (anonymous):

I moderate like a boss.

OpenStudy (anonymous):

can i be a moderator too?

myininaya (myininaya):

he won't allow me to be pink im upset

OpenStudy (anonymous):

I would, but I have no control over such things

myininaya (myininaya):

lol im kidding

OpenStudy (anonymous):

i hve never seen this green before

OpenStudy (anonymous):

i want to be orange

myininaya (myininaya):

hey satellite, amistre is also green

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