Question

soybean meal is 16% protein; cornmeal is 8% protein how many pounds of each should be mixed together in order to get 320lb mixture that is 10% protein

Answer 1

i think i have done this exact problem maybe 8 times. write
\[.16x+.08(230-x)=32\] and sovle for x

Answer 2

actually it is
\[.16x+.08(320-x)=32\]

Answer 3

Use x + y = 320 and .16x + .08y = .10 Solve the system

Answer 4

i get 80
of course you can use two varialbes if you like

Answer 5

but if you do it should be
\[.16x+.08y=32\]

Answer 6

\[.16x+.08(320-x)=32\] because if you use x soybeans you use 320-x cormeal and 10% of 320 is 32

Answer 7

so how many pounds of cornmeal should be in the mix
and how many pounds of soybean should be in the mix

Answer 8

\[.16x+25.6-.08x=32\]
\[.08x+25.6=32\]
\[.08x=32-25.6=6.4\]
\[x=\frac{6.4}{.08}=80\]

Answer 9

80 cornmeal the rest soybeans

Answer 10

I am subtracting 32 from 80 to get the soybean

Answer 11

or is the soybean 32

Answer 12

Its a lot easier to me if you use the substitution method

Answer 13

tervin03 can you show me how to arrive at the answer by using that method

Answer 14

0Use x + y = 320 and .16x + .08y =32 and use the substitution method. So in the first equation x + y = 320 you can subtract x from both side to get y = 320 - x and substitute it in the second equation making it .16x +.08(320 - x) =32

Answer 15

Solve it for x and then back substitute the answer in the first original equation x + y = 320 to get y

Answer 16

Tervin03
so how many pounds of cornmeal should be in the mix
and how many pounds of soybean should be in the mix

Answer 17

Soybean is 80 and cornmeal is 240