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Mathematics 28 Online
OpenStudy (anonymous):

Assume straight-line appreciation..... An antique clock is expected to be worth \$475 after 3 years and \$870 after 6 years. What will the clock be worth after 9 years?

OpenStudy (anonymous):

Presuming straight-line appreciation means that the value goes up evenly (ie, at the same rate), note here that they gave you two prices separated by exactly 3 years, and are asking you for a new value, again exactly 3 years later. Find the difference between the two prices over the 3 year time period, then add that back to the 6 year price to get the 9 year price. (It's essentially slope you're using here.)

OpenStudy (anonymous):

Sorry, I'm still not getting it...

OpenStudy (anonymous):

Look at it this way: At year #3 it was worth \$475, and at year #6 it was worth \$870. That means it went up \$870-\$475 = \$395 in exactly 3 years. Now they want to know what it'll be like in year #9. They mention "straight-line appreciation", which means the value goes up at the exact same rate all of the time. Since we already know it'll go up \$395 in 3 years, and we know that year #9 just happens to be exactly 3 years after year #6....we can add \$395 to the value at year #6 to get the final value.

OpenStudy (anonymous):

LOL! Now I feel like a real dummy! I was trying to use the equations and making it really harder on myself! Thanks for your help!

OpenStudy (anonymous):

NP...if they had asked you for a different time span, say year #10, you'd have to find the slope (algebra concept), then use that...would have been harder.

OpenStudy (anonymous):

The book only gives depreciation and uses the slope formula! So I was just trying to make it harder! I've been cramming for Biology and Psychology also! Think I've bite off more than I can chew this summer!

OpenStudy (anonymous):

Good luck with that...sounds like fun.

OpenStudy (anonymous):

Thanks, no fun yet! :(

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