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Mathematics 25 Online
OpenStudy (anonymous):

the width of a rectangle is fixed at 14cm what lenghts will make the perimeterr greater than 72cm? the length must be greater than --cm

OpenStudy (anonymous):

perimeter of a rectangle is 2* width + 2*length > 72 if the width is fixed at 14, then 28 + 2*length > 72 2*length > 72-28 length > (72-28)/2

OpenStudy (anonymous):

oojih.com is the answer 22

OpenStudy (anonymous):

let me check the math, 72-28 = 44 yes, it is 22

OpenStudy (anonymous):

thanks very much

OpenStudy (anonymous):

np, i hope you understand how to set up the problem.

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