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OpenStudy (anonymous):
the width of a rectangle is fixed at 14cm what lenghts will make the perimeterr greater than 72cm? the length must be greater than --cm
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OpenStudy (anonymous):
perimeter of a rectangle is 2* width + 2*length > 72 if the width is fixed at 14, then 28 + 2*length > 72 2*length > 72-28 length > (72-28)/2
OpenStudy (anonymous):
oojih.com is the answer 22
OpenStudy (anonymous):
let me check the math, 72-28 = 44 yes, it is 22
OpenStudy (anonymous):
thanks very much
OpenStudy (anonymous):
np, i hope you understand how to set up the problem.
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