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OpenStudy (anonymous):

What are the "graph shifts" for the equation y =4sin(pi*x+2)-5 ? how do you graph this?

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OpenStudy (anonymous):

graph shifts in -ve x by an amount of 2/pi and it goes upward by an amount 5

OpenStudy (anonymous):

ye i got that but i cant graph it right. dnt know why

OpenStudy (anonymous):

OpenStudy (anonymous):

i have the graph infront of me. the thing i dont understand is why the the shift looks like pi/2 when it is meant to be 2/pi ?

OpenStudy (anonymous):

see the graph has shifted only by an amount which is less than 1 towards -ve x. so the shift is 2/pi not pi/2 as pi/2 is greater than 1

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