Question

one last question and im going to bed can factorization help solve a quadratic equation if it is made up of a prime polynomial

Answer 1

yes it can help if u try to do so

Answer 2

can you give an example

Answer 3

ok wait

Answer 4

no no sorry i didn't read u wrote prime polynomial AS IF THERE ARE PRIME POLYNOMIAL NOTHING CAN BE TAKEN COMMON SO ANSWER IS NO :)

Answer 5

Do you mean prime coefficients and constant?

Answer 6

normal definition of "prime" means that it cannot be factored. of course you need refrence to what "ring; you are factoring over. example
\[x^2-2\] is "prime" over the integers but
\[x^2-2=(x+\sqrt{2})(x-\sqrt{2})\] if you are factoring over reals.
similarly
\[x^2+1\] is prime over reals but is
\[(x+i)(x-i)\] if you allow complex numbers