Ask your own question, for FREE!
Mathematics 25 Online
OpenStudy (anonymous):

one last question and im going to bed can factorization help solve a quadratic equation if it is made up of a prime polynomial

OpenStudy (anonymous):

yes it can help if u try to do so

OpenStudy (anonymous):

can you give an example

OpenStudy (anonymous):

ok wait

OpenStudy (anonymous):

no no sorry i didn't read u wrote prime polynomial AS IF THERE ARE PRIME POLYNOMIAL NOTHING CAN BE TAKEN COMMON SO ANSWER IS NO :)

OpenStudy (anonymous):

Do you mean prime coefficients and constant?

OpenStudy (anonymous):

normal definition of "prime" means that it cannot be factored. of course you need refrence to what "ring; you are factoring over. example \[x^2-2\] is "prime" over the integers but \[x^2-2=(x+\sqrt{2})(x-\sqrt{2})\] if you are factoring over reals. similarly \[x^2+1\] is prime over reals but is \[(x+i)(x-i)\] if you allow complex numbers

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
NaiNoah: should it hurt when i move/flex my thigh?
1 hour ago 7 Replies 3 Medals
Gucchi: english help.
11 hours ago 8 Replies 1 Medal
Gucchi: .. english help
13 hours ago 5 Replies 1 Medal
Gucchi: english help
13 hours ago 10 Replies 2 Medals
Gucchi: english HELP
14 hours ago 10 Replies 2 Medals
Gucchi: ````````````` english help
14 hours ago 7 Replies 1 Medal
Gucchi: english help `
17 hours ago 11 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!