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Mathematics 23 Online
OpenStudy (anonymous):

2. Given the surface: f ( x, y ) = (e^ x + y) + ln( y^ 2 + x) a. Show that the point (0,1) is located on the curve f ( x, y ) = e , and find the equation of the tangent line to the curve, at that point. b. Find the slope of the tangent line to the curve, that results from the intercept of the plane x = 0 with the surface, at the point where y = 1 . c. Find the slope of the tangent line to the curve, that results from the intercept of the plane y = 1 with the surface, at the point where x = 0 . how to solve this kind of questions? explanation will be very-very appreciated)

OpenStudy (anonymous):

the point (0,1) does not lie on the curve f(x,y) =e

OpenStudy (anonymous):

the point (1,0) lies on that curve make sure you asked the question correctly

OpenStudy (anonymous):

no formatting went wrong. but solution is less crucial-i am fine with this part. I am lost with theory. what steps should i use?

OpenStudy (anonymous):

I mean algebraicly i can manage whatever, but I just dont und what is asked and what to do

OpenStudy (anonymous):

which part? a, b, or c?

OpenStudy (anonymous):

a-i just make it all equal to e and plug in point. b and c-no idea

OpenStudy (anonymous):

is this a calculus question?

OpenStudy (anonymous):

it is as i und next course after calculus

OpenStudy (anonymous):

we have not just x and y, but also z. so it is threedomential or how to call it

OpenStudy (anonymous):

the plane where x is 0 is the y-z plane.

OpenStudy (anonymous):

substitute x =0 and y =1 and find the value of z at that point.

OpenStudy (anonymous):

i think it is one step ahead. we are not asked for plane, we asked to find line. so it is (x,y) probably

OpenStudy (anonymous):

so you are basically trying to find the slope of the tangent plane at the point (0,1,2)

OpenStudy (anonymous):

oh wait hold on.

OpenStudy (anonymous):

i have surface. so i need to understand about which curve in this surface we are talking and find tanget line to it in a specific points. that is how i understand it

OpenStudy (anonymous):

what you suggest is different-does not look right to me((

OpenStudy (anonymous):

the point on the curve is (0,1,2) correct? you need to find the tangent to the curve at that point.

OpenStudy (anonymous):

what you suggest is different-does not look right to me((

OpenStudy (anonymous):

probably)

OpenStudy (anonymous):

btw-tangent line in this case means that i should find partial derivative?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and my next step? lets assume i already got Fx and Fy

OpenStudy (anonymous):

my calculus is a bit rusty. let me read up on this. be back in a bit.

OpenStudy (anonymous):

sure thank you for your time

OpenStudy (anonymous):

did you find out \[f_x and f_y\]?

OpenStudy (anonymous):

no yet, should I?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

sec

OpenStudy (anonymous):

got it

OpenStudy (anonymous):

Fx=(e)^(x^2+y)*2x+1/y^2+x*2y

OpenStudy (anonymous):

I have never heard about normal vector. which means it probably different material

OpenStudy (anonymous):

ignore that.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

see the example in that.

OpenStudy (anonymous):

almost. but again it is different material. it is not tangent plane. we dont work with planes here really. we find curves and work with curves

OpenStudy (anonymous):

hmmm

OpenStudy (anonymous):

well, I suggest you wait for dumbcow or amistre64 or one of the others. They are good with calculus. Meantime, I'll try and read up on this problem and see if I can help.

OpenStudy (anonymous):

my first step-i should understand what is my curve. then i have to find derivative. then plug in values if needed. my main problem-i dont understand how do i know about which curve they are asking and how do i find it. this step from surface to curve is totally unclear for me

OpenStudy (anonymous):

then would be nice to understand how do i find one tangent line having two derivatives

OpenStudy (anonymous):

your curve is z = (e^x + y) + ln( y^2+ x)

OpenStudy (anonymous):

sec

OpenStudy (anonymous):

the derivative to that curve will give you a tangent plane.

OpenStudy (anonymous):

it is e in a power of x^2+Y plus ln(y^2 +X)

OpenStudy (anonymous):

huh?

OpenStudy (anonymous):

lol, yes. hard to write it normally

OpenStudy (anonymous):

well, whatever the curve is, you get the tangent plane to that curve when you find the derivative of the curve.

OpenStudy (anonymous):

it is obvious. but steps are not

OpenStudy (anonymous):

oh now I understand the line they are talking about is the line created by the tangent plane to the curve.

OpenStudy (anonymous):

no tanget plane here. just lines.

OpenStudy (anonymous):

have you done tangent planes before? if not, its kinda hard to visualize.

OpenStudy (anonymous):

well, thats the only interpretation I can see of the problem. Maybe Im reading it wrong. sorry couldn't be of more help

OpenStudy (anonymous):

I know how does this space looks like. for example circle looks like a huge vase with sticks out of it

OpenStudy (anonymous):

but such visualizing does not help me to solve the problem. does not matter. you probably did not cover this yet.

OpenStudy (anonymous):

but let me get back to you when I've researched this a bit, but I think my interpretation is right.

OpenStudy (anonymous):

ok i will go over notes again.

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

oh no, I have done all this about 10 years ago. I don't remember the specifics. Don't use math all that much these days for my job :)

OpenStudy (anonymous):

My gosg how old are you? I though everybody here are around 15-20

OpenStudy (anonymous):

lol, i'm 25

OpenStudy (anonymous):

I am 26

OpenStudy (anonymous):

no kidding! are you majoring in math?

OpenStudy (anonymous):

It is my first year in university.

OpenStudy (anonymous):

oh okay. great! which university?

OpenStudy (anonymous):

RRIS, Israel

OpenStudy (anonymous):

And as you can guess i finished school 10 years ago-so since that i did not see math at all. now everything from the beggining

OpenStudy (anonymous):

oh okay. Yeah, thats a hassle. I don't remember much from what I studied in high school either. well, I hope someone else comes along and helps you out. good luck!

OpenStudy (anonymous):

thank you)

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