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OpenStudy (anonymous):

how do you do this sum??? "use the factor theorem to determine whether g(x)is a factor of p(x):

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OpenStudy (anonymous):

(i) p(x) = \[2x ^{3} + x ^{2}-2x-1,if g(x)=x+1

OpenStudy (anonymous):

you have a choice. you can replace x by -1 in p(x). if you get 0 then x+1 is a factor.

OpenStudy (anonymous):

in ohter words if p(-1)=0 then p(x)=(x+1)Q(x)

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

when it says " use the factor theorem, that is what it wants you to do

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OpenStudy (anonymous):

or you could just divide but that doesn't use the theorem

OpenStudy (anonymous):

or you could just divide but that doesn't use the theorem

OpenStudy (anonymous):

no the theorems what i need

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