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How do you find the area of an acute triangle when you're only given the side lengths????
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one way is; you can use the law of cosines to find an angle and use that angle in the side*side*sin(angle)/2 formula
the other is to use herons formula
so the area = \[a timesb \times \sin \] of the angle contained between a and b?
then, divided by two
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thats right; so if you can find the angle between two sides, you can find the area
okay! Thanks :)
in my picture; base = b; height = a sin(angle) which fits into the normal Area = b*h/2 that you are familiar with
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