Question

use the substitution to solve the following equation

4x-y-3z=-3
x-2y-2z=-3
x+y+3z=-2

a. -1 2 -1
b. 1 -2 1
c. -1 -2 1
d.1 -2 -1

NEED HEEEEELPPPPPPP

Answer 1

sorry i need substitution form

Answer 2

x+y+3z=-2
y=-x-3z-2

Answer 3

use y=-x-3z-2 subtitution and solve

Answer 4

thanks

Answer 5

4x-( )-3z=-3
plug -x-3z-2 inside parenthese

Answer 6

4x-y-3z=-3
4x-( -x-3z-2 )-3z=-3
4x+x+3z+2-3z=-3
5x = -3-2
x=-5/5
x=-1

Answer 7

x-2(-x-3z-2)-2z=-3
x+2x+3z+4 -2z =-3
x +z =-3-4
x+z =-7

Answer 8

x+y+3z=-2

-1+y+3z=-2
y + 3z = -2+1
y + 3z = -1

Answer 9

-2y-2z = -2
y + 3z = -1 ( time 2) 2y+6z = -2
-2y-2z = -2
2y+6z = -2
-----------------------
Add 4z = -4

z=-1

Answer 10

x+y+3z=-2
subtitution x=-1, z=-1 solve for y
-1 +y+3(-1)=-2
y -3-1 = -2
y -4 = -2
y = -2+4
y = 2
the answer is a

Answer 11

good night