solve using the addition and multiplication principles..1+3x

Question

solve using the addition and multiplication principles..1+3x<28

angela210793 · Answer

1+3x<28(-1 both sides)
3x<28-1
3x<27(divide with 3 both parts)
x<27/3
x<9
x belongs to]-infinite;9[

anonymous · Answer

$$\left\{ x \left| x \ge9 \right| \right\}$$

anonymous · Answer

that is the answer I have

anonymous · Answer

1+3x<28(-1 both sides)
3x<27(divide both sides with 3)
x<9

angela210793 · Answer

well no...the answer is the one i found....y did u equal it?

anonymous · Answer

i have to put it into a solution set. oh i clicked on the wrong sign

angela210793 · Answer

w8

anonymous · Answer

it should be that shouldnt it?

angela210793 · Answer

$$x \in]-\infty;9[$$

angela210793 · Answer

x must be only less than 9, not 9 or less

anonymous · Answer

if i put 9 in for x it would be 1+3(9)<28
                                             1+28<28
                                               29<28
                     that look about right?

anonymous · Answer

nope thats not right either

angela210793 · Answer

so the inequality isn't right cause 29>28

anonymous · Answer

1+3(9)<28
   1+27<28
      28=28

angela210793 · Answer

anyway 9 would be included only if it said  $$1+3x \le28$$

anonymous · Answer

so i just need to change my symbol to the other direction?

angela210793 · Answer

the symbol must be <

angela210793 · Answer

Got it Tena?

anonymous · Answer

yes thanks.

angela210793 · Answer

:)

anonymous · Answer

good angela

angela210793 · Answer

:P:P:P
I did pretty good in my math exam :):)

anonymous · Answer

heyy yea congrats

angela210793 · Answer

Thnx :)