Question

Find all the zero's of f:

f(t) = (t - 3)2 - (t + 3)

Answer 1

t = 3

Answer 2

is it (t-3)2 or (t-3)^2 ?????

Answer 3

multiply it out and combine like terms

Answer 4

Sorry I had a sign error; the answer should be 9

Answer 5

@tad
I think the 2 in the first term shud b square.....

Answer 6

if it is (t-3)^2 - (t+3), then
= t^2 -6t +9 - t -3 (using the identity (a-b)^2 = a^2 - 2ab + b^2)
= t^2 - 7t + 6
= t^2 - t - 6t + 6
= t(t-1) -6(t -1)
= (t-6)(t-1)

Answer 7

if f(t) = 0
=> (t-6)(t-1) = 0
this is possible if either of the two factors is zero
if t-6 = 0 => t = 6
if t-1 = 0 => t = 1

so zeros of f(t) are 1 and 6

Answer 8

which one is correct nany?????????

Answer 9

i got the las answer

Answer 10

if u have to write square of something use the upward pointing carat ^ before the index

eg
3 squared = 3^2

square of (x +9) = (x+9)^2

cube of (z-j) = (z-j)^3