Question

find the intercepts of f(x)=3x^2+2x-5

Answer 1

(x - 1 ) (3x +5) = 0
x = 1
x = -5/3

Answer 2

i got this one can you help me with \[f(x)=\sin ^2x+\cos ^2x, x=9\pi/4\]

Answer 3

sin^2 (x) + cos^2 (x) = 1, always, so f(x) = 1.

f(9pi/4) = (sin 9pi/4)^2 + (cos 9pi/4)^2 = (sin 45°)^2 + (cos45°)^2 = (sqrt2/2)^2 + (sqrt2/2)^2 = 2/4 + 2/4 = 4/4 = 1