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Mathematics 9 Online
OpenStudy (anonymous):

solve the triangle

OpenStudy (anonymous):

OpenStudy (amistre64):

given 3 sides, we can use the law of cosines to find an angle

OpenStudy (amistre64):

\[\frac{c^2-a^2-b^2}{-2ab}=cos(C)\]

OpenStudy (anonymous):

wats the answer

OpenStudy (anonymous):

can u help with this one

OpenStudy (amistre64):

lol .... the answer is what you get when you fill in the s bs and cs

OpenStudy (amistre64):

the parabola one can be tricky; you have to go with the geometric definition

OpenStudy (anonymous):

takin a quiz i really need the answers lol

OpenStudy (amistre64):

x^2 + 4x -2y -2 = 0 x^2 +4x = 2y+2 x^2 +4x +4 = 2y+2+4 (x+2)^2 = 2(y+3) that looks better; thats in the form of x^2=4ay

OpenStudy (amistre64):

if you simply want someone to give you answers to a quiz; thats against the anti cheating policy of openstudy

OpenStudy (anonymous):

i just really need to pass this class bro

OpenStudy (amistre64):

but if you need help finding the answers, I can step you thru them :) but working for free to get you a good grade just aint my style ... But I aint the only one here, so maybe we can get someone to produce answers :)

OpenStudy (anonymous):

thanks

OpenStudy (amistre64):

(x+2)^2 = 2(y+3) the vertex is defined by what is modifying the x and ^ ^ y parts of this equation ^ ^ just negate them can you give it a shot?

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