Question

this stupid thing is winning, help me beat it!

The length of a rectangle is 5 more than twice the width. if the perimeter is 58cm, find the dimensions

Answer 1

does it set up as 58 = 2+5?

Answer 2

no

Answer 3

2x I mean

Answer 4

width = 8 cm
lenght = 21 cm

Answer 5

whoa whoa, length is not 5w, it is 2w+5... right?

Answer 6

5 more than twice the length is what it says

Answer 7

my answer isn`t wrong Snapier?

Answer 8

Lol. Complete misread. Yeah. So you have 2l+2w=58
l=2w+5
4w+20+2w=58
6w=48
w=8
Then l=2(8)+5
l=21

Answer 9

Thats right^^

Answer 10

I am just trying to make sure I understand how to set up the equation, I never checked yoru answer Paul

Answer 11

ok, sweet... beers all around!

Answer 12

:D

Answer 13

So friend..... u have a system like that

5 + 2W = L .... A
2L + 2W = 58 .... B

then, for example for solve it, take (B - A)
this implie in a new equation C like that

2L - 5 = - L + 58 ... C
then
3L = 63 \[\rightarrow\] L = 21

insert it in eq. A we have
5 + 2W = 21

solving \[\rightarrow 2W =16\]
W = 8

Answer > \[L = 21 cm , W = 8 cm\]