Question

how do you do qs 6 and 9???
http://monmouth.monmoodle.co.uk/file.php?file=%2F187%2FMEI%20A-LEVEL%20HOMEWORK%20RESOURCES%2FM1%2FM1%20Multiple%20Choice%2FMC%20Motion%204.pdf
thanks :)

Answer 1

I don't see anything.

Answer 2

http://monmouth.monmoodle.co.uk/file.php?file=%2F187%2FMEI%20A-LEVEL%20HOMEWORK%20RESOURCES%2FM1%2FM1%20Multiple%20Choice%2FMC%20Motion%204.pdf
try it again please, it sometimes goes funny :S

Answer 3

#6 average velocity is distance traveled / time elapsed. time elapsed is 10
distance traveled is area under the curve, which you find by the area of the triangles

Answer 4

first triangle has area
\[\frac{1}{2}10\times 3=\frac{5}{3}\]

Answer 5

second triangle has area
\[\frac{1}{2}4\times 10=20\]

Answer 6

ok i made a mistake. first triangle has area 15 not
\[\frac{5}{3}\] sorry

Answer 7

15+20=35, divide by 10 get 3.5

Answer 8

so answer to #5 is 35 and answer to #6 is 3.5

Answer 9

if you answered #8 then divide by 8 to get answer to #9

Answer 10

can you help me with qs 9 please???

Answer 11

So it asks for displacement after 8 seconds
let first find displacement after 6 seconds by find area under the under graph

Answer 12

6*6*1/2=18

Answer 13

now 6 to 8 second by find area that triangle
2*2*1/2=2
remember that this is negative velocity
18-2=16

Answer 14

THANK YOU SOOO MUCH :)

Answer 15

don't forget to divide by 8 to get average!