Question

factor W^3+8=

Answer 1

= ?

Answer 2

That's the sum of two perfect cubes. Do you remember that formula?

Answer 3

w^3 + 8 = 0

w^3 = -8

third sqrt of -8 = -2

Answer 4

Yeah, its \[a^3 \pm b^3\]

Answer 5

I thought it was what went into 8

Answer 6

The formula is:

a3 + b3 = (a + b)(a2 – ab + b2)

Answer 7

\[(w \pm 3)(w^2 \pm w*3 + 9)\]

Answer 8

The second plus/minus should be upside down.

Answer 9

So it'd be

\[\left( w+2 \right)\left( w ^{2}-2w+4 \right)\]

Answer 10

@Mooby: the b = 3, not 2.