Question

x=y^2-3y+2 ; find y

Answer 1

??

Answer 2

x=(y-2)(y-1)
y=1,2
sorry

Answer 3

???

Answer 4

that is an x, not a zero!

Answer 5

the soln is wrong there is x not 0

Answer 6

when x = 0

Answer 7

sweet if you meant 0 then infauzan has it. if you meant x you are going to have to solve a quadratic equation

Answer 8

oooh yeah

Answer 9

thank you, you are so talented

Answer 10

just solve it in terms of x

Answer 11

i will not speculate what the problem is, because if you really meant x this is going to be somewhat of a pain. you are going to have to write
\[y^2-3y+(2-x)=0\] and use
\[y=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] whith
\[a=1, b = -3, c=2-x\] so maybe this wasn't the actual question

Answer 12

@ him x is already solved for

Answer 13

i have a feeling that the x is supposed to be a 0 and infauzan has it

Answer 14

yes im only saying we can leave the answer in terms of x

Answer 15

it looks more like a quadratic equation like satellite says, which is simple to work out and it will have 2 answers.. \[0=y ^{2}-3y+2\] which can be factorized to:
\[0=y ^{2}-2y-1y+2\]
\[0=2y(y-2)-1(y-2)\]
\[0=(2y-1)(y-2)\]
therefore y=
\[2y=1\]
\[y=0.5\]
and y also equals:
\[y=2\]