Question

Look at the following sequence of numbers. 1 8 6 3 9 2 8 5 7 2. If the sum of the first and third number is greater than the than the sum of the second and fifth number, then circle the eighth.

Miss Von Thaden tried very hard to make sure that nobody was left out during PE class. She thought she had a correct head count and told the students to pair up. This didn't work because there was one person who left out. She then told them to get into groups of five, but this didn't work either because again there was one person left over. Finally, she decided to try groups of four.

Answer 1

what are we suppose to do

Answer 2

1+6=7
8+9=17
7 is not greater than 17 so we dont circle the 8th term

Answer 3

Miss Von Thaden doesn't have to leave anyone out of PE class.

Answer 4

Sorry I couldn't fit all of it.

*Again, one person left out. There are fewer than 80 students in the class. How many were present on this particular day.

Answer 5

Well, she didn't have an even number, but she did have a multiple of five + 1.

Answer 6

So, that would be 11, 21, 31, 41, 51, 61, or 71.

Answer 7

And if pairing up doesn't work, then neither will groups of 4.

Answer 8

is that it?

Answer 9

Groups of 7 will work if there are 21 students.

Answer 10

no, 11 is not an answer, and neither is 31,51 or 71

Answer 11

51 would work for groups of 3.

Answer 12

21 would also work for groups of 3.

Answer 13

@dhatraditya how is it wrong?

Answer 14

your choices of answers are limited to 21, 41 and 61.

Answer 15

The rest are prime ... 11, 31, 41, 61, 71.

Answer 16

because if you paired 11 in groups of 4, you will have 3 left out, not one. same applies for 31, 51 and 71

Answer 17

@dhatraditya 41 and 61 would work if you had groups of 1

Answer 18

any number would work for groups of 1