solve indefinite integral (lnx)^-1

Question

anonymous · Answer

$$\int\limits 1/lnx$$

anonymous · Answer

let u=ln(x)

anonymous · Answer

du/dx = 1/x

dx= x du = e^u du

anonymous · Answer

so then you have integral e^u / u , which should be possible to do by parts, hopefully

anonymous · Answer

@elecengineer...

its not possible to solve by parts ..
the series will continue on and on and on ...

anonymous · Answer

$$\int\limits u^{-1} e^u du $$

m = e^u  ,       u^(-1) du =  dn 

dm/du = e^u  ,   n = -1/(u^2)

anonymous · Answer

i tried the same

anonymous · Answer

yeh I wouldnt worry bout it, I looked at it for a few minutes then went to wolframa

anonymous · Answer

anonymous · Answer

if wolframa cannot do it then theres a pretty good chance that it cant be done by hand

anonymous · Answer

wait isnt their a reduction formula for integrals of the form x^n e^x

anonymous · Answer

anonymous · Answer

or is that only for positive n

anonymous · Answer

i checked wolframa too it says Lix

wat is Lix?

anonymous · Answer

what i linked to, the Logarithmic Integral