Question

square root 5x^2 -3x =2x solve each radical equation and check the answer help

Answer 1

\[\sqrt{5x^2-3x}=2x\] ?

Answer 2

yes

Answer 3

square both sides
\[5x^2-3x=(2x)^2\]
\[5x^2-3x=2^2*x^2\]
\[5x^2-3x=4x^2\]
subtract 4x^2 on both sides
\[5x^2-4x^2-3x=4x^2-4x^2\]
\[x^2-3x=0\]
now factor
\[x(x-3)=0\]

Answer 4

\[\sqrt{5x ^{2}-3x}=2x\]
\[5x ^{2} -3x =4x ^{a}\]
5x^2-4x^2-3x=0
x(x-3)=0
x=0,x=3

Answer 5

x=0 or x=3
but since we squared both sides lets check our answers
we see for 0 it is true
it is true for x=3
\[\sqrt{5*3^2-3*3}=\sqrt{45-9}=\sqrt{36}=6\]
other side we have 3*2=6
so both sides are the same
:)x=0 and x=3 are both solutions

Answer 6

thank you