If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.

x – 3y – 3z = –13
x + 2y – z = –1
2x + 3y + 2z = 0
Answer
x – 3y = –13
2x + 3y = 0

2x + 3y = 0
4x + 7y = –2

x – 3y = –13
–2x – 9y = –10

–2x – 9y = –10
4x + 7y = –2

Question

If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.

x – 3y – 3z = –13
x + 2y – z = –1
2x + 3y + 2z = 0
Answer    
x – 3y = –13
2x + 3y = 0

2x + 3y = 0
4x + 7y = –2

x – 3y = –13
–2x – 9y = –10

–2x – 9y = –10
4x + 7y = –2

radar · Answer

What did you get when you eliminated z in the first 2?

anonymous · Answer

i dont know

radar · Answer

When you complete the elimination of z in the first two equation you will have to multiply every thing in equation  two by 3.  You will then subtract this from equation 1.  This will result in a 0z  or eliminating the z.  I gotta run good luck.