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How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 40% antifreeze solution?
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12(.40-.20)/(1-.20) ... maybe?
these are the options : A. 2 gallons B. 8 gallons C. 4 gallons D. 6 gallons
gonna have to review my thoughts on that one :)
a(1) + 12(.20) = (12+a)(.40) a(1) + 12(.20) = 12(.40)+a(.40) a(1-.40) = 12(.40-.20) a = 12(.40-.20)/(1-.40) ... I was thiiiisssss close lol
so whats the answer?
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im gonna assume your smart enough to actually pick up at least a calculator and enter the numbers ...
4 gallons
lol. ok thanks
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