Question

5| x + 2 | > - 10

Answer 1

i think i did that. O

Answer 2

:O

Answer 3

this one has a -10 tho :0

Answer 4

Oh, okay!

Answer 5

x + 2 > -2

x + 2 > + 2

Answer 6

x + 2 > -2
x > -4

x + 2 > + 2
x > 0

Answer 7

master khan you are forgetting to flip one of the inequalities

Answer 8

umm, where? :O

Answer 9

Correct me!

Answer 10

Plz.

Answer 11

y u changed the sign on the right side?

Answer 12

think if we have |x|>3

then we have x>3 or x<-3
~~~~~~~* *~~~~~
---------|------|-------
-3 3
everything less than -3 is a solution since |everything less than -3|>3

and

everything more than 3 is a solution since |everything more than 3|>3

Answer 13

so if the MOD is on the "X".

so it means that X can be -ve or +ve..
Am I right?

Answer 14

OK, now i got that... thats A TON! :D

Answer 15

what happens if we have a negative on the other side
if we |x|>-3
x>-3, x<3
()~~~~~~~()
-------|---------|---------
-3 3

|2|=2<-3

but -4 and 4 is a solution since |-4|>3 and |4|>3

so but it is the other way around when you have a negative on the other side

so maybe if we have |x|>-3 then we have
x>3 or x<-3

Answer 16

|x+2|>-2

so we have
x+2<-2 and x+2>2
x<-4 and x>0
~~~() ()~~~~
----|-----|------
-4 0

Answer 17

somebody please awnser is correctly?

Answer 18

we can check our answer by randomly choosing numbers in the solution set to check
what about -5?
-5 is suppose to be in the solution set

5|-5+2|=5|-3|=5(3)=15>-10

how about 5?
5 is suppose to be in the solution set

5|5+2|=5|7|=35>-10

so we have the correct solution sets now
(-inf,-4)U(0,inf)

Answer 19

lol

Answer 20

:O

Answer 21

Messed Up!

Answer 22

Fully. :/

Answer 23

solution is (-inf,inf)
all real numbers

just graph both y= 5|x+2| and y=-10
you will see that y=5|x+2| is always above y=-10