Question

Let us say a Company uses codes to represent its various products
a codes includes, among other information, a character in tenth position
that represents the zone from which that product was made, and 4 digits
integer in position 4 thru 7 that represents the district in which it will
be sold. Due to some reorganization, products from zone R are banned
from being sold in districts with a designation of 2000 or higher.
Writ a complete program to count and print number of banned and valid code entered.
Example: TRV2475A5R-14 valid
TRL2k74A5R-11 : distr


JAVA

Answer 1

this problem meets your requirements and please notify if some enhancement can be done

Answer 2

import java.util.Scanner;
class code
{
public static void main(String arg[])
{

char arr[]=new char[4];
Scanner sc=new Scanner(System.in);
System.out.print("Enter the code of product");
String str=sc.nextLine();
if(str.length()<13 || str.length()>13)
{
System.out.println("the code is invalid");

code.main(arg);
}
else
{
// char ch=str.charAt(4);
//System.out.print(ch);
//System.out.print(str);
try
{
for(int i=0;i<4;i++)
{
arr[i]=(str.charAt(i+3));

}
}
catch(Exception ex)
{
System.out.print("The numeric values not found");
}
int x=0;
int add=1000;
int xr[]=new int[4];
try
{
for(int i=0;i<4;i++)
{
Character ch=arr[i];
String strs=ch.toString();
int ssx=Integer.parseInt(strs);
xr[i]=ssx;
x=x+(ssx*add);
add=add/10;
}




if(str.charAt(9)=='R'&& x>=2000 && check(xr)==false)
{
System.out.print("The above code product has been banned in this district or it is not from zone R");
}
else
System.out.print("this product code is valid ");


}

catch(Exception ex)
{

System.out.print("Invalid code");



}
}
}
static boolean check(int ara[])
{
int count=0;
for(int i=0;i<4;i++)
{
if(Character.isDigit(ara[i]))
{
count++;

}
else
{
}
}
if(count==0)
return false;
else
stro:

return true;

}

}

Answer 3

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