Question

A child has six tiles. Each tile is emblazoned with one of the following letters: G, H, I, J, K, or L. How many different three-letter arrangements ( such as HKG) can the child craft if G is always the last letter in the arrangement and one of the letters in the arrangement is K?

Answer 1

8 ways

Answer 2

how?

Answer 3

m i correct ?

Answer 4

There are no answer choices so im not sure.

Answer 5

so the middle one can be arranged anyway. so the answer is 4

Answer 6

well i say that...

we have six letters to chose from...
nd we have to make a three lettered word from those
now let ( _ _ _ ) be the word
last place can only have g ..
so it can be filled in ony one way....

and the word need to have a "k"
k can be either in first place or second ... [2 possibilities for it)

and the remaining last place can be filled in only four ways becoz we have only four letters left....

so there is one possibilty for last place ..
2 possibilities for letter k ..
and 4 possibilities for the remainag place..
hence the totel no. of words formed are 4.2.1.= 8

[fundamental principle of counting ]

Answer 7

Oh sorry, didnt see that K can be first or second. But yeah, I agree with you now.