Question

the equation formed by decreasing each root of ax^2 + bx + c = 0 by 1 is 2x^2 + 8x + 2 = 0. Then
a. c=-a
b. b=-c

Answer 1

roots of this are
\[-2\pm\sqrt{3}\] so roots of original equation are
\[-1\pm\sqrt{3}\]

Answer 2

1) Find roots of 2x^2 + 8x + 2 = 0
2) Define a function that has the same roots, only this time increased by one
3) Check which statement is true.

Answer 3

i dint get both ...got something else!!

Answer 4

multiply
\[(x-(-1+\sqrt{3}))(x-(-1-\sqrt{3}))\] to get original equation

Answer 5

which is actually a lot easier than it looks

Answer 6

"first"
\[xx=x^2\]
"last"
\[(-1+\sqrt{3})(-1-\sqrt{3})=1-3=-2\]

Answer 7

x^2 -2x√3+2x+4 ??

Answer 8

and "outer, inner" is
\[(1+\sqrt{x})x+(1-\sqrt{3})x=2x\]

Answer 9

to give
\[x^2-2x+2=0\]

Answer 10

i looks hard at first glance but it is easy to multiply this out. check what i wrote

Answer 11

thanks a lot... :)

Answer 12

yw

Answer 13

is the answer b ?