Mathematics
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OpenStudy (anonymous):
The area of a rectangle is 84cm^2. The perimeter is 40cm find the dimensions.
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OpenStudy (saifoo.khan):
xy = 84 --- 1
2y+2x = 40 ---2
OpenStudy (saifoo.khan):
Solve by substituion!
myininaya (myininaya):
Area of rectangle=A=xy=84
P=2x+2y=40
myininaya (myininaya):
xy=84
2x+2y=40=> x+y=20
OpenStudy (anonymous):
do it the cool way! solve this quadratic equation:
\[p^2-20p+84 = 0\]
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OpenStudy (anonymous):
so 5 and 15
myininaya (myininaya):
lol the cool way
OpenStudy (anonymous):
@CabRamos youre close, but 15*5 doesnt equal 84, so thats not the correct answer >.<
myininaya (myininaya):
y(x+y)=y(20)
xy+y^2=20y
y^2+xy-20y=0
y^2+84-20y=0
y^2-20y+84=0
(y-6)(y-14)=0
OpenStudy (anonymous):
6 and 14 then?
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OpenStudy (anonymous):
nice :)
OpenStudy (anonymous):
Thanks ha
myininaya (myininaya):
gj!
OpenStudy (anonymous):
could it also be 16 and 4?
OpenStudy (anonymous):
yes that is correct too
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OpenStudy (anonymous):
cause both of those are options on my worksheet
myininaya (myininaya):
16 and 4?
16(4) is not 84
OpenStudy (anonymous):
whoops >.< 14 and 6. i got confused >.<
OpenStudy (anonymous):
i thought he just switched the order >.< my bad my bad.
myininaya (myininaya):
if y=6, then x=14
if y=14, then x=6
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OpenStudy (anonymous):
joe did u ever figure out the pool question?