Question

Im on ps5 problem 3 and i cant figure out why this wont work
http://pastebin.com/eU3AhWuN

Answer 1

maybe because your attempting to iterate through a dic when all you have is a list :(

Answer 2

Your main problem is that you are not iterating through all the words in word_list. In other words, use a loop (hint ---> for loop). Also, you have forgotten to make sure that the word can be made with the letters in the current hand.

Answer 3

I don't think has.key() works for lists I think it is only for dictionaries (that have keys).

Answer 4

oops I didn't read your answer to yourself (in 3rd person...?) which says the same. double_o_seven suggests a good way to do it, you could also try bisection method if you are keen on it.

Answer 5

'in' works for lists and dictionaries ... word in word_list

Answer 6

bwCA is correct.
The first test is is the word in the word list. A statemtent like "if not (word in word_list) : return false" will get your there. But, this is the easy part. The second test is to determine if the word is made up of letters in hand. For this I made a copy of hand. I Iterated though the letters in word and subtacted them out of the copy of hand. This is a scetchy explanation but hopefully it points in the right direction.

Answer 7

Another approach is to convert the word to a dictionary using get_frequency_dict, and then compare the values of the indices of the two dictionaries "word" and "hand". e.g. word={'a':1, 'c':1, 't':1} and hand={'a':1,'b':1} then hand.get('c') < word.get('c') and therefore 'cat' isn't a valid word.