Question

Qudratic equations..x^2 - 4x = 12

Answer 1

imaginary roots.no real roots

Answer 2

\[x^2-4x-12=0\]
\[(x-6)(x+2)=0\]
so
\[x=6\ or \ x=-2\]

Answer 3

Ok that what I got but the answer sheet is telling me 2,6,12,16

Answer 4

solve it using completing the square method
add square of half of the coefficient of x i.e. 4/2 = 2 to both sides

x² - 4x + 2² = 12 + 2²
LHS takes the form a² - 2ab + b² = (a - b)²
(x - 2)² = 16
taking root of both sides
x-2 = ± root(16)
x = 2 ± 4
x = 2+4 =6
and
x = 2-4 = -2

Answer 5

x = 6, x = -2

Answer 6

The answer sheet is wrong.

Answer 7

6

Answer 8

or -2

Answer 9

u can substitute the values into the equation and calculate...
you will that -2 and 6 r the right answers..