Question

f(x)=x^3+8
find all zeros by factoring each function.

Answer 1

hi

Answer 2

x=2

Answer 3

no

Answer 4

-2

Answer 5

is right

Answer 6

they has 3 different result, yours is one (-2)

Answer 7

3 result ???

Answer 8

yes

Answer 9

looke x^3 +8=0
x^3 =-8 = -2^3

Answer 10

{-2, 1+i sqrt 3, 1-i sqrt3

Answer 11

I think 3^+8= (x+2)(x^2-2x+4)

Answer 12

so x=-2 and x^2-2x+4 will give other two results

Answer 13

use squardric formular to do it

Answer 14

I think you gone

Answer 15

yes is right and you need to calculate x from x+2 from this will get x=-2
and from x^2 -2x +4
2+/- radical (4-16) 2(1+/- i radical 3)
x_1,2 = ------------------ = ----------------- = 1+/- i radical 3
2 2

radical hope that you know equal sqrt

Answer 16

hope that this is clearly

Answer 17

yesbu i in this case is 1^2?

Answer 18

i in this case is (-1)^2?

Answer 19

sorry what is this what you have wrote ?

Answer 20

I don't understand why you use i-radial 3. What is i ?

Answer 21

I think i = (-1)^2

Answer 22

if you see there is x_1,_2 = (2+/- sqrt (4-16))/2
and here from sqrt(-12) you get 2i sqrt 3 but after you simplified with 2 will remain this resulte

Answer 23

now is clearly ?

Answer 24

so sqrt (-2)^* 3 = i sqrt 3

Answer 25

yes it is clear

Answer 26

sqrt(-2)^3 = sqrt (-2^2)*2 =2i sqrt 2 because i^2 = -1

Answer 27

ok

Answer 28

i understand now

Answer 29

ok bye

Answer 30

thanks for ur help

Answer 31

was my pleasure