Question

its a division... and i think i did it right but i'm not sure.. 9x^4y^3+18x^2y-27xy^4 / 9x^2y^3 the answer i got was x^2+2/y^2-3y/x... did i get it?

Answer 1

don't think so...
let me try

Answer 2

divide /cancel out nominator & denominator by (9x^2 y^3), left:
x^2 +2 x y^(-26)

Answer 3

yeah i did that... i divided the 9,18 and 27 by 9 from the bottom and cancelled out any of the leftover letters so i had the x squared = the 2 [from the 18] over the y squared minus the 3[leftover from the 27] and a y over the x

Answer 4

do you agree with the answer?

Answer 5

i made it three peroblems then put them all together at the end

Answer 6

did you get the same answer?

Answer 7

whats the -26 you have on a post

Answer 8

power of y:
y^(-27)*y^4/y^3=y^-26

Answer 9

9x^4y^3 + 18x^2y - 27xy^4
---------------------------
9x^2y^3

separating into three separate fractional terms

9x^4y^3 18x^2y 27xy^4
--------- + --------- - ---------
9x^2y^3 9x^2y^3 9x^2y^3

Now cancelling out common terms from the numerators and denominators
2 3 y
x^2 + ----- - ------
y^2 x

Answer 10

@kmo

yr answer is right......

Answer 11

sorry... I mis-red your equation :(
I thought that y in a power of (-27)...

Answer 12

o! thats okay- makes me feel good that i got it right haha thank you for your help =]

Answer 13

good job!!
:)