Question

Am I able to evaluate sin(cos^1(7/11)) without a calculator? If yes, how?

Answer 1

Is that supposed to be cosine inverse?

Answer 2

Yes

Answer 3

\[\text{Sin}\left[\text{ArcCos}\left[\frac{7}{11}\right]\right]\]

Answer 4

You want to draw the right triangle associated with that. Im trying to think of a better way to explain it >.<

Answer 5

\[\cos^{-1}(\frac{7}{11}) \Rightarrow \cos(\theta) = \frac{7}{11}\]
and in a right triangle:
\[\cos(\theta) = \frac{adj}{hyp}\]
You want to draw that right triangle.

Answer 6

\[cos(\theta) = \frac{7}{11} = \frac{adj}{hyp}\]
\[adj^2 + opp^2 = hyp^2\]

Answer 7

\[sin(\theta) = \frac{opp}{hyp}\]

Answer 8

so find opp using the Pythagorean triangle and then put it over the hypotenuse.

Answer 9

6(rad2)/11