Question

perform the indicated operation:
x^3-8/x^2+2x+4 ÷ (x^2-4)

Answer 1

okay u just have to factor and then divide!

Answer 2

still lost

Answer 3

note that \[8 = 2^3\]

Answer 4

\[4=2^2\]

Answer 5

\[x^3-8 = x^3 -2^3\]

\[x^2-4 = x^2 -2^2\]

Answer 6

ok i got 2/x+1

Answer 7

how?

Answer 8

ahh i dont know i think i factored wrong

Answer 9

you need to know the formulas for
\[a^2-b^2 \]
and
\[a^3-b^3\]
google them if you don't know the formulas already.

Answer 10

\[\frac{x^3-8}{x^2+2x+4} ÷ (x^2-4)\]
\[=\frac{(x-2)(x^2+2x+4)}{(x^2+2x+4)} \div (x-2)(x+2)\]
\[=\frac{(x-2)(x^2+2x+4)}{(x^2+2x+4)} \times \frac{1}{(x-2)(x+2)}\]
\[=\frac{1}{(x+2)}\]

Answer 11

hakkunamatata, we generally try to get the students to work on their problems themselves. We don't do their problems for them.

Answer 12

yep

Answer 13

right

Answer 14

whywhywhy!!!!