Question

What is the vertex of y=x^2-11x+28

Answer 1

Do u want to know how to do this?

It's the same procedure every time...

Answer 2

vertex=(5/2,0)

Answer 3

Yes .

Answer 4

ax^2 + bx + c
x^2-11x+28

So this case, a is 1, b is -11 and c is 28, agreed?

Answer 5

- Sure .

Answer 6

So then u use -b/2a to get the x-coordinate of the vertex.

So plug in the values we just found and what do u get?

Answer 7

7 and 4 ?

Answer 8

U understand? If not, say...

Answer 9

a is 1, b is -11 so what is

-b/2a ?

Answer 10

- Was I right or wrong ?

Answer 11

I don't know where u got 7 and 4 from?

a is 1, b is -11 and we want -b/2a

Answer 12

- That was one of my options , thee other ones didnt make sense . :/

Answer 13

Ah! Those are the zeros, you asked for the vertex.

Answer 14

Huh ?

Answer 15

This your question above:

What is the vertex of y=x^2-11x+28?

Answer 16

Is that the right question? If so

a is 1, b is -11 and we want -b/2a

Answer 17

r u not able to do that?

Answer 18

No .

Answer 19

Is it just answers u r looking for?

Answer 20

- That would be nice , but I would also like to understand .

Answer 21

The simple way just to get the answers is to feed your equation into Wolfram like this (it's easy)

http://www.wolframalpha.com/input/?i=x^2-11x%2B28

Answer 22

The problem with understanding is that it will be very difficult to explain things if u do not understand how to do basic operations like calculating -b/2a for two numbers a and b.