Question

How would I rationalize the denominator in sqrt[3]/ (sqrt[3] - 2)? I've forgotten how to do it...

Answer 1

multiply top and bottom by sqrt3 + 2

Answer 2

multiply by the conjugate

Answer 3

And multiplying it by the conjugate would just give me 3- 2 in the denominator, right?

Answer 4

3-4

Answer 5

That's right, thanks...

Answer 6

sqrt[3] sqrt[3] + 2 {sqrt[3]}² + 2sqrt[3] 3 + 2sqrt[3]
--------- * ----------- = ------------------ = ------------
sqrt[3] - 2 sqrt[3] + 2 {sqrt[3]}² - 2² 3 - 4

3 + 2sqrt[3]
= -------------- = -3 -2sqrt[3]
-1