Question

Determine the vertx of the parabola whose equation is f(x)=x^2-8x+7.
Next find the minimum or maximum value.
What is the x-intercepts?

Answer 1

vertex=-b/2a=8/2=4
4^2-8*4+7=-9
(4,-9)
the x^2 is positive so the parabola faces up so theres a minimum value
minimum is the same as the vertex

x intrecepts is where y=0
0=x^2-8x+7
(x-7)(x-1)=0
x=7,1
so
(1,0) & (7,0)

Answer 2

Thank you!

Answer 3

np