Question

I need to factor 2x^3-16

Answer 1

Factor out and 2 and you will have difference of cube

Answer 2

2x^3=16
x^3=8
Now try what i tried in the last problem.but this time with 16

Answer 3

SOMEONE GIVE IT TO ME STEP BY STEP! Haha, thank you. :)

Answer 4

http://en.wikipedia.org/wiki/Factorization#Sum.2Fdifference_of_two_cubes

Answer 5

\[a^3-b^3=(a-b) \left(a^2+a b+b^2\right)\]

Answer 6

x^3-8
=(x-2)(x^2 +2x-4)
= x=2
In general a3 - b3 = (a - b)(a2 + ab + b2)

Answer 7

So in this problem b=2.52??? and a=x???

Answer 8

b=2,a=x

Answer 9

How is b=2????

Answer 10

you need to try and convert 8 to the form of b^3

Answer 11

OOOOHHHH! So you divide by 2 first!!! Gotcha now, ok

Answer 12

Not exactly divide, we try and finding the factors of 8 in such a way they repeat thrice.Like 2*2*2

Answer 13

I kind of get it......

Answer 14

Similarly with -27, when you factorise it, you get -3*-3*-3. I mean look for these factors rather than,
3*3*-3

Answer 15

So when I substitute do I say -8 or 8?

Answer 16

I get it now, haha

Answer 17

here, when you frame your equation, it becomes
x^3=8. So you try to factoris 8 in terms of a cube not -8

Answer 18

ok, so 8

Answer 19

So is my final answer (x+3)(x^2+8x+64)?

Answer 20

No, b^3 =8 not b.
so it will be (x-2)(x^2+2x+4)=0
this when expanded gives x^3-8=0

Answer 21

OH! So b=2

Answer 22

yep!