Question

What is the derivative of INVERSE trig functions?

Answer 1

There is a formula that gives the derivative of the inverse function.
f'(x)*[f^-1(x)]' = 1
The product of derivative of a function and the derivative of the inverse of function is 1.

Answer 2

Derivative is Differentiation , Right?

Answer 3

Correct.

Answer 4

I was just curious, watched a youtube video and it baffled me. I will ask my maths teacher, unless anyone thinks they can give a thorough and indepth explanation of it.

Answer 5

I just Know the Formulas ..nothing more then that ..A lil about Inverse but not derivation of inverse derivative

Answer 6

Hey Here I've got an Idea

For tangent function

Answer 7

We Know \[1 + tan^2{\theta} = sec^2{\theta}\]

Answer 8

I'm not familiar with this, sorry. I have no clue. I will ask my mahts teacher.

Answer 9

Hey I went wrong but Look at sin function

\[sin^s + cos^2s = 1\]

and We also know that
\[sin^{-1}s + cos^{-1}s =\frac{ \pi}{2}\]

Answer 10

$$(asinx)'=\dfrac{1}{\sqrt{1-x^2}} $$
$$(acosx)'=\dfrac{-1}{\sqrt{1-x^2}} $$
$$(atanx)'=\dfrac{1}{1+x^2} $$
$$(acotanx)'=\dfrac{-1}{1+x^2} $$

$$asin=sin^{-1}$$
$$acos=cos^{-1}$$
$$atan=tan^{-1}$$
$$acotan=cotan^{-1}, cotanx=\dfrac{1}{tanx}$$

Answer 11

chaise if you are interested go here
http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e3282890b8ba7b2da416d1f

Answer 12

go to the bottom i derived some of these for you

Answer 13

well actually for ishaan

Answer 14

Wow, thank you so much! I didn't even expect you to do this, it must have taken so long! Thank you muchly.

Answer 15

not really lol
these are fun