Question

write the equation of the line that is parallel to y=1/3x-3 and passes through point (6,2)

Answer 1

The equation is already in the form of \(y=mx+c\), where \(m\) is the slope, so we know the slope is \(\frac{1}{3}\). Parallel lines have the same slope, so this is the slope of the new line as well.

The formula for the equation of the line is \[y-y_{1} = m(x-x_{1})\]
\(y-2 = \frac{1}{3}(x-6)\) using the point (6,2)

\(3y-6=x-6\)
\(3y=x\)

Answer 2

so you just plug in the 6 and the 2?

Answer 3

Yep

Answer 4

oooh okay thanks